[13-3(x-2y)]+4(3x+y)=

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Solution for [13-3(x-2y)]+4(3x+y)= equation:


Simplifying
[13 + -3(x + -2y)] + 4(3x + y) = 0
[13 + (x * -3 + -2y * -3)] + 4(3x + y) = 0
[13 + (-3x + 6y)] + 4(3x + y) = 0

Remove brackets around [13 + -3x + 6y]
13 + -3x + 6y + 4(3x + y) = 0
13 + -3x + 6y + (3x * 4 + y * 4) = 0
13 + -3x + 6y + (12x + 4y) = 0

Reorder the terms:
13 + -3x + 12x + 6y + 4y = 0

Combine like terms: -3x + 12x = 9x
13 + 9x + 6y + 4y = 0

Combine like terms: 6y + 4y = 10y
13 + 9x + 10y = 0

Solving
13 + 9x + 10y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-13' to each side of the equation.
13 + 9x + -13 + 10y = 0 + -13

Reorder the terms:
13 + -13 + 9x + 10y = 0 + -13

Combine like terms: 13 + -13 = 0
0 + 9x + 10y = 0 + -13
9x + 10y = 0 + -13

Combine like terms: 0 + -13 = -13
9x + 10y = -13

Add '-10y' to each side of the equation.
9x + 10y + -10y = -13 + -10y

Combine like terms: 10y + -10y = 0
9x + 0 = -13 + -10y
9x = -13 + -10y

Divide each side by '9'.
x = -1.444444444 + -1.111111111y

Simplifying
x = -1.444444444 + -1.111111111y

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